Tuesday, June 10, 2014
Monday, February 24, 2014
Thursday, December 12, 2013
LabVIEW - WEbsite Link
Review :
I have gone through the various websites regarding the LabVIEW course . The Telemark university college website is very useful to the beginners. I suggest that you can go through this website. This sites contains step by step procedure ,sample codes and also great strength of this site having the option to take the online Quiz test. I Personally thanks to this author and the departments which provide the materials on the net.
Thanks
LabVIEW WEbsite link-Telemark University College
Thursday, November 28, 2013
Tuesday, October 29, 2013
MPMC Lab Model Qeustions - EC2307
EC2307 – Microprocessors and Microcontroller Lab Model Exam Question Paper
1. Write an
assembly language program for performing the Addition and Subraction of two byte numbers using 8086
Microprocessor.
2. Write an
assembly language program for performing the Multiplication and Division of 16 bit numbers using 8086
Microprocessor.
3. Write an
assembly language program to sort a given array in Ascending and Descending order with array of length 10
using 8086 Microprocessor.
4. Write an
assembly language program to find Largest and Smallest number in a given Array using 8086 Microprocessor.
5. Write an
assembly language program to move string of length FF from source to destination using 8086 Microprocessor.
6. Write an
assembly language program for Modes of operation of programable timer 8253.
7. Write an
assembly language program for performing Addition and Subraction of two 8 bit numbers using 8051 Microcontroller
and store the results in memory.
8. Write
an assembly language program for performing the Multiplication and Division of two 8 bit data using 8051 and store the
result in memory.
9.Write
an assembly language program for performing communication between 8051 Micrcontroller kit and PC.
10. Write
an assembly language program to verify timer, interrupts and UART operations in 8051 Microcontroller.
11. Write
an assembly language program for interfacing 8279, 8259 with 8085 Microprocessor.
12. Write
an assembly language program to convert Analog signal into Digital signal using ADC interfacing using 8086
Microprocessor.
13. Write
an assembly language program for Digital to Analog converter using 8086 Microprocessor.
14. Write
an assembly language program to convert Digital inputs into Analog outputs and to generate different waveforms using
8086 Microprocessor.
15. Write
an assembly language program in 8086 to rotate the motor at different speeds (using Stepper motor and DC motor).
16. Write
an assembly language program in 8086 to display the rolling message “WELCOME” in the display.
17. Write
an assembly language programby interfacing 8255 with 8086 in Mode0, Mode1 and Mode2.
Sunday, October 13, 2013
Placement online Test , GATE free online Test and TNPSC Group online test website
Recently i have gone through the website www.tamilcube.com which is one among best website for so many things. This website contains the different categories like e books and dictionaries etc. Some
Features of this site :
- Topic for placement activities and government exams
- This site offers the online mock test series in free of cost.
- We can verify the answer and also it has answer with explanation.
- GK test
- UPSC TNPSC Prepararion
- Verbal and aptitude test etc....
We can practice the test without any login procedure
Thanks to the Tamilcube.com website team
Another website
www. exam2win.com . This website requires the login id and password which can be obtained totaly free. We can practice more questions.
Thanks to www.exam2win.com website teams.
Another website
www. exam2win.com . This website requires the login id and password which can be obtained totaly free. We can practice more questions.
Thanks to www.exam2win.com website teams.
Thursday, October 10, 2013
Interfacing of Microprocessor Unit III - EC2304 MPMC Question
1.
Give the Salient
features of 8253 timer module
2.
What is an sample and
hold circuit
3.
List out the major
function performed by CRT interface
4.
List out the four
display modes of 8279 keyboard /display controller
5.
What are the commonly
used ADC and DAC ‘s?
6.
Formulate the control
word for setting bit PC4 high using BSR mode
7.
What is the purpose of
AC flag available in Intel processors?
8.
What is key bouncing?
9.
Write down the control
word format of SCON and TMOD Register
10. Determine the control word for the following configuration of 8255:- Port A
– Output
Mode of port A – Mode 1
Port B – Output
Mode of port B – Mode 0
Port C lower (pins PC0 – PC2) – Output
11. What is 8254? Discuss its
various operating modes.
What are its
areas of applications?
12. What is interfacing?
13. List the operating modes of the 8255A programmable device.
14.
What is the internal
frequency of the 8279? How can you drive from any available clock signal?
Part B
- 1. Explain the 8279 keyboard and display controller with neat sketch.
- 2. Describe the architecture and working of 8253 timer and also explain the various operating modes
- 3. With diagram, explain the operation of R-2R method of D/A Converter
- 4. Explain the function of CRT terminal interface
Sunday, October 6, 2013
ADDRESSING MODES OF 8086
ADDRESSING MODES OF 8086
Addressing mode indicates a way of locating data or operands. Depending
upon the data types used in the instruction and the memory addressing modes,
any instruction may belong to one or more addressing modes, or some instruction
may not belong to any of the addressing modes. Thus the addressing modes
describe the types of operands and the way they are accessed for executing an
instruction. Here, we will present the addressing modes of the instructions
depending upon their types.
According to the flow of
instruction execution, the instructions may be categorized as
(i)
Sequential control flow
instructions and
(ii)
Control transfer
instructions.
Sequential control flow instructions are the instructions, which after execution, transfer control to the
next instruction appearing immediately after it (in the sequence) in the
program. For example, the arithmetic, logical, data transfer and processor
control instructions are sequential control flow instructions.
- Immediate: In this type of addressing, immediate data is a
part of instruction, and appears in the form of successive byte or bytes.
Example: MOV AX, 0005H
In the above example, 0005H is the immediate data. The immediate data may
be 8-bit or 16-bit in size.
- Direct: In the direct addressing mode, a 16-bit memory
address (offset) is directly specified in the instruction as a part of it.
Example: MOV AX,
[5000H]
Here, data resides in a memory location in the data segment, whose Physical
address may be computed using 5000H as the offset address and content of DS as
segment address. The Physical address, here, is 10H*DS+5000H.
- Register: In register addressing mode, the data is stored
in a register and it is referred using the particular register. All the
registers, except IP, may be used in this mode.
Example: MOV BX, AX.
- Register
Indirect:
Sometimes,
the address of the memory location, which contains data or operand, is
determined in an indirect way, using the offset registers. This mode of
addressing is known as register indirect mode.
In this addressing mode, the offset address of data is in either BX or SI
or DI registers. The default segment is either DS or ES. The data is supposed
to be available at the address pointed to by the content of any of the above
registers in the default data segment.
Example: MOV AX, [BX]
Here, data is present in a memory location in DS whose offset address is
in BX. The Physical address of the data is given as 10H*DS+ [BX].
- Indexed: In this addressing mode, offset of the operand
is stored in one of the index registers. DS and ES are the default
segments for index registers SI and DI respectively. This mode is a
special case of the above discussed register indirect addressing mode.
Example: MOV AX, [SI]
Here, data is available at an offset address stored in SI in DS. The Physical
address, in this case, is computed as 10H*DS+ [SI].
- Register
Relative:
In this
addressing mode, the data is available at an Physical address formed by
adding an 8-bit or 16-bit displacement with the content of any one of the
registers BX, BP, SI and DI in the default (either DS or ES) segment. The
example given before explains this mode.
Example: MOV Ax, 50H [BX]
Here, Physical address is given as 10H*DS+50H+ [BX].
- Based
Indexed:
The Physical
address of data is formed, in this addressing mode, by adding content of a
base register (any one of BX or BP) to the content of an index register
(any one of SI or DI). The default segment register may be ES or DS.
Example: MOV AX, [BX]
[SI]
Here, BX is the base register and SI is the index register. The Physical
address is computed as 10H*DS+ [BX] + [SI].
- Relative
Based Indexed:
The Physical
address is formed by adding an 8-bit or 16-bit displacement with the sum
of contents of any one of the bases registers (BX or BP) and any one of
the index registers, in a default segment.
Example: MOV AX, 50H
[BX] [SI]
Here, 50H is an immediate displacement, BX is a base register and SI is
an index register. The Physical address of data is computed as 160H*DS+ [BX] +
[SI] + 50H.
The
control transfer instructions:
The addressing modes depend upon whether the
destination location is within the same segment or a different one. It also
depends upon the method of passing the destination address to the processor.
Basically,
there are two addressing modes for the control transfer instructions, viz. inter-segment
and intra-segment addressing modes.
If the
location to which the control is to be transferred lies in a different segment
other than the current one, the mode is called inter-segment mode. If
the destination location lies in the same segment, the mode is called
intra-segment.
Inter-segment
Direct 
Inter-segment Inter-segment
Indirect
Modes for
control
Transfer instructions
Intra-segment 
Intra-segment Direct
Intra-segment
Indirect
Addressing Modes for
Control Transfer Instruction
9.
Intra-segment direct mode:
In this mode, the address to which the control is to be transferred lies
in the same segment in which the control transfer instruction lies and appears
directly in the instruction as an immediate displacement value. In this
addressing mode, the displacement is computed relative to the content of the
instruction pointer IP.
The Physical
address to which the control will be transferred is given by the sum of 8 or 16
bit displacement and current content of IP. In case of jump instruction, if the
signed displacement (d) is of 8 bits (i.e. –128<d<+128), we term it as
short jump and if it is of
16 its
(i.e. –32768<+32768), it is termed as long jump.
In this mode, the
displacement to which the control is to be transferred, is in the same segment
in which the control transfer instruction lies, but it is passed to the
instruction indirectly. Here, the branch address is found as the content of a
register or a memory location. This addressing mode may be used in
unconditional branch instructions.
11. Inter-segment
Direct Mode:
In this mode,
the address to which the control is to be transferred is in a different
segment. This addressing mode provides a means of branching from one code
segment to another code segment. Here, the CS and IP of the destination address
are specified directly in the instruction.
12.Inter-segment Indirect Mode:
In this mode,
the address to which the control is to be transferred lies in a different
segment and it is passed to the instruction indirectly, i.e. contents of a
memory block containing four bytes, i.e. IP (LSB), IP (MSB), CS (LSB) and CS
(MSB) sequentially. The starting address of the memory block may be referred
using any of the addressing modes, except immediate mode.
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